Answer:
The perimeter of triangle PQR is 17 ft
Step-by-step explanation:
Consider the triangles PQR and STU
1. PQ ≅ ST = 4 ft (Given)
2. ∠PQR ≅ ∠STU (Given)
3. QR ≅ TU = 6 ft (Given)
Therefore, the two triangles are congruent by SAS postulate.
Now, from CPCTE, PR = SU. Therefore,
Now, side PR is given by plugging in 3 for 'y'.
PR = 3(3) - 2 = 9 - 2 = 7 ft
Now, perimeter of a triangle PQR is the sum of all of its sides.
Therefore, Perimeter = PQ + QR + PR
= (4 + 6 + 7) ft
= 17 ft
Hence, the perimeter of triangle PQR is 17 ft.
Answer:
Option H
Step-by-step explanation:
Perimeter of rectangle= 2(length) +2(width)
100= 2(5a -22) +2[½(a +1)]
Expand:
100= 2(5a) +2(-22) +a +1
100= 10a -44 +a +1
Simplify:
100= 11a -43
+43 on both sides:
11a= 100 +43
11a= 143
Divide both sides by 11:
a= 143 ÷11
a= 13
Thus, option H is correct.
The graph will be as shown in attached figure
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