Given that
the weight of football players is distributed with a mean of 200 pounds and a standard deviation of 25 pounds.
And we need to find What is the minimum weight of the middle 95% of the players?
Explanation -
Using the Empirical Rule, 95% of the distribution will fall within 2 times of the standard deviation from the mean.
Two standard deviations = 2 x 25 pounds = 50 pounds
So the minimum weight = 200 pounds - 50 pounds = 150 pounds
Hence the final answer is 150 pounds.
I believe the answer would be inconsistent and dependent, and also inconsistent and independent. System of equations with three variables are either independent, dependent or inconsistent , each case can be established algebraically and represented graphically.
X = 15 , see photo for solutions
Answer:
21
Step-by-step explanation:
Try using this notation: a(n) and not an.
an=n^3-2n becomes a(n) = n^3 - 2n.
Then a(1) = 1^3 - 2(1) = 1 - 2 = -1
a(2) = 2^3 - 2(2) = 8 - 4 = 4
a(3) = 3^3 - 2(3) = 27 - 6 = 21
Answer:
no
Step-by-step explanation:
8÷ 1/2
Copy dot flip
8 * 2/1 = 16
Divide 8 things in half you get 16
1/2 of 8 = 1/2 * 8 = 4
Half of 8 things is 4
They are not the same
