A container holds 1 mole of helium gas. The volume of the container is 2 liters and the pressure inside the container is 105.0 k
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Answer:
pOH of resulting solution is 0.086
Explanation:
KOH and CsOH are monoacidic strong base
Number of moles of in 375 mL of 0.88 M of KOH =
= 0.33 moles
Number of moles of in 496 mL of 0.76 M of CsOH =
= 0.38 moles
Total volume of mixture = (375 + 496) mL = 871 mL
Total number of moles of in mixture = (0.33 + 0.38) moles = 0.71 moles
So, concentration of in mixture,
=
Hence,