Answer: Option C. 8,064 pounds
Solution:
Unit weight: U=63 pounds/foot^3
Total Weight: W=?
W=U*V
Volume: V
Length: l=8 feet
Width: w=4 feet
Height: h=4 feet
V=l*w*h
Replacing the knwon values in the formula above:
V=(8 feet)*(4 feet)*(4 feet)
V=128 feet^3
Replacing in the formula of total Weight:
W=U*V
W=(63 pounds/foot^3)*(128 feet^3)
W=8,064 pounds
Answer:
1: C(n) = 2.50 + 16n
2: $66.50
Step-by-step explanation:
Part 1
Each ticket costs $16 per person. If tickets for n persons were purchased, the total cost would be 16n.
There is also a one-time service fee of $2.50 that must be paid. Thus, for n tickets the total cost is
C(n) = 2.50 + 16n
Part 2
For n = 4, the expression evaluates to
C(4) = 2.50 + 16 (4) = $66.50
Answer:
Step-by-step explanation:
Hello!
We can use the difference of square method.
<h2>Difference Of Squares (DOS)</h2>
The formula for the DOS is
It is a simple way to factor polynomials.
The criteria:
- Has to begin and end with a perfect square
- The operation has to be subtraction
<h3>Factor:</h3>
Begins with a perfect square (x² * x²) and ends with a perfect square (4 * 4)
Warning! Watch out, there may be another DOS!
is another DOS
The x² + 4 is not a DOS because the operation is addition.
The final factored form is
Answer:
<h3>x = (-2)</h3><h3>y = 2</h3>
Step-by-step explanation:
2x + 3y = 6________( 1 )
-3x + 5y = 10_______( 2 )
( 1 ) × 3 ---- 6x + 9y = 18_____( 3 )
( 2 ) × 2 ---- -6x + 10y = 20_____( 4 )
y = 2 ,
Answer:
1) Fail to reject the Null hypothesis
2) We do not have sufficient evidence to support the claim that the mean distance students traveled to school from their current residence was different for males and females.
Step-by-step explanation:
A university administrator wants to test if there is a difference between the distance men and women travel to class from their current residence. So, the hypothesis would be:
The results of his tests are:
t-value = -1.05
p-value = 0.305
Degrees of freedom = df = 21
Based on this data we need to draw a conclusion about test. The significance level is not given, but the normally used levels of significance are 0.001, 0.005, 0.01 and 0.05
The rule of the thumb is:
- If p-value is equal to or less than the significance level, then we reject the null hypothesis
- If p-value is greater than the significance level, we fail to reject the null hypothesis.
No matter which significance level is used from the above mentioned significance levels, p-value will always be larger than it. Therefore, we fail to reject the null hypothesis.
Conclusion:
We do not have sufficient evidence to support the claim that the mean distance students traveled to school from their current residence was different for males and females.