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evablogger [386]

2 years ago

9

Help please . Lost .

1 answer:

9966 [12]2 years ago

8 0

<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em>

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Solve 7.8e^((x/3)ln(5))=14. What are the exact and approximate solutions?

Dimas [21]

$\bold{\text{Answer}:\quad x=3\bigg(\dfrac{ln\frac{14}{7.8}}{ln(5)}\bigg)=1.09}$

<u>Step-by-step explanation:</u>

$7.8e^{\frac{x}{3}\cdot ln(5)}=14\\\\\\e^{\frac{x}{3}\cdot ln(5)}=\dfrac{14}{7.8}\\\\\\ln\bigg(e^{\frac{x}{3}\cdot ln(5)}\bigg)=ln\bigg(\dfrac{14}{7.8}\bigg)\\\\\\\frac{x}{3}}\cdot ln(5)=ln\bigg(\dfrac{14}{7.8}\bigg)\\\\\\\large\boxed{x=3\bigg(\dfrac{ln\frac{14}{7.8}}{ln(5)}\bigg)}\\$

x ≈ 1.09

6 0

2 years ago

A desk is 2 meters long and 1 meter wide. The desk needs to be represented in a scale drawing of an office that uses a scale of

Strike441 [17]

Answer:

<em>Thus, the dimensions of the desk in the drawing are 4 cm long and 2 cm wide.</em>

Step-by-step explanation:

<u>Scaling</u>

The scale factor established to represent a desk 2 meters long and 1 meter wide is:

1 centimeter = 0.5 meter

We need to convert the real dimensions to the scaled dimensions. To complete the task, it's a good idea to multiply the real dimensions by the ratio:

$\displaystyle \frac{1\ cm}{0.5\ m}$

to get the scaled dimensions.

The length of 2 meters is scaled to:

$\displaystyle 2\ m\frac{1\ cm}{0.5\ m}=4\ cm$

And the width of 1 meter is scaled to:

\displaystyle 1\ m\frac{1\ cm}{0.5\ m}=2 cm

Thus, the dimensions of the desk in the drawing are 4 cm long and 2 cm wide.

3 0

2 years ago

Can someone help me solve F(x) = -9x-5

USPshnik [31]

Answer:

Step-by-step explanation:

What you've provided is only a function. What's the complete question?

7 0

2 years ago

A bakery wants to determine how many trays of doughnuts it should prepare each day. Demand is normal with a mean of 5 trays and

Alexeev081 [22]

Answer:

4 trays should he prepared, if the owner wants a service level of at least 95%.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 5

Standard Deviation, σ = 1

We are given that the distribution of demand score is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(X > x) = 0.95

We have to find the value of x such that the probability is 0.95

P(X > x)

$P( X > x) = P( z > \displaystyle\frac{x - 5}{1})=0.95$

$= 1 -P( z \leq \displaystyle\frac{x - 5}{1})=0.95$

$=P( z \leq \displaystyle\frac{x - 5}{1})=0.05$

Calculation the value from standard normal z table, we have,

$\displaystyle\frac{x - 5}{1} = -1.645\\x = 3.355 \approx 4$

Hence, 4 trays should he prepared, if the owner wants a service level of at least 95%.

3 0

2 years ago

Translate this phrase into an algebraic expression:

krek1111 [17]

Jesus is the lord above all

3 0

2 years ago