Answer:
19.74% of temperatures are between 12.9°C and 14.9°C
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
What proportion of temperatures are between 12.9°C and 14.9°C?
This is the pvalue of Z when X = 14.9 subtracted by the pvalue of Z when X = 12.9.
X = 14.9
has a pvalue of 0.2420
X = 12.9
has a pvalue of 0.0446
0.2420 - 0.0446 = 0.1974
19.74% of temperatures are between 12.9°C and 14.9°C
Answer:
f(g(x)) = 722, and g(f(x)) = 154
Step-by-step explanation:
f(x) = 2x²
g(x) = 3x + 4
g(f(x)) = 3(2x²) + 4
g(f(5)) = 3(2 × 5²) + 4
g(f(5)) = 3(2 × 25) + 4
g(f(5)) = 3 × 50 + 4
g(f(5)) = 154
f(g(x)) = 2(3x + 4)²
f(g(5)) = 2(3 × 5 + 4)²
f(g(5)) = 2 × 19²
f(g(5)) = 2 × 361
f(g(5)) = 722
Step-by-step explanation:
According to this trigonometric function, −C gives you the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL:
![\displaystyle Phase\:[Horisontal]\:Shift → \frac{0}{4} = 0 \\ Period → \frac{2}{4}π = \frac{π}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Phase%5C%3A%5BHorisontal%5D%5C%3AShift%20%E2%86%92%20%5Cfrac%7B0%7D%7B4%7D%20%3D%200%20%5C%5C%20Period%20%E2%86%92%20%5Cfrac%7B2%7D%7B4%7D%CF%80%20%3D%20%5Cfrac%7B%CF%80%7D%7B2%7D)
Therefore we have our answer.
Extended Information on the trigonometric function
![\displaystyle Vertical\:Shift → D \\ Phase\:[Horisontal]\:Shift → \frac{C}{B} \\ Period → \frac{2}{B}π \\ Amplitude → |A|](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Vertical%5C%3AShift%20%E2%86%92%20D%20%5C%5C%20Phase%5C%3A%5BHorisontal%5D%5C%3AShift%20%E2%86%92%20%5Cfrac%7BC%7D%7BB%7D%20%5C%5C%20Period%20%E2%86%92%20%5Cfrac%7B2%7D%7BB%7D%CF%80%20%5C%5C%20Amplitude%20%E2%86%92%20%7CA%7C)
NOTE: Sometimes, your <em>vertical shift</em> might tell you to shift your graph below or above the <em>midline</em> where the amplitude is. Moreover, ALL <em>tangent</em>,<em> </em><em>secant</em>, <em>cosecant</em>, and <em>cotangent</em> functions have NO AMPLITUDE.
I am joyous to assist you anytime.
Answer:
The opposite sides of the rectangle are parallel.
Step-by-step explanation:
If that is true for all parallelograms and a rectangle is a parallelogram, then it should be true for a rectangle too, I think.
Answer:
where is the options? or is any given.
Step-by-step explanation:
