Answer:
1440 ft squared
Step-by-step explanation:
v = lwh (length times with time height)
Hope this helps Buddy!
- Courtney
Answer:
a.) Between 0.5 and 3 seconds.
Step-by-step explanation:
So I just went ahead and graphed this quadratic on Desmos so you could have an idea of what this looks like. A negative quadratic, and we're trying to find when the graph's y-values are greater than 26.
If you look at the graph, you can easily see that the quadratic crosses y = 26 at x-values 0.5 and 3. And, you can see that the quadratic's graph is actually above y = 26 between these two values, 0.5 and 3.
Because we know that the quadratic's graph models the projectile's motion, we can conclude that the projectile will also be above 26 feet between 0.5 and 3 seconds.
So, the answer is a.) between 0.5 and 3 seconds.
Answer:
2 or 4
Step-by-step explanation:
Since I do not quite understand what you mean by X X, I could think of two answers. If you are doing 5 times X=20, then X = 4, but if you are trying to do 5 times x times x, then x=2.
The answer is C. Identify property of addition
Answer:
Is there answer options because if not then it would possibly be y = 45x + 540 or it could be 45x = 540 or it could be 45x/540 so it can be any of those :)
Step-by-step explanation: