Ask question

Ask question

All categories

2 years ago

15

An experiment consist of rolling Two fair number cubes. find the probability of each event.

1 answer:

slega [8]2 years ago

5 0

Probability = (number of possible successes) / (number of total possibilities).

<u>Number of total possibilities:</u>
Each cube can come up in 6 different ways.
Total number of possibilities = 6 x 6 = 36

<u>Possible successes:</u>
There are 2 different ways to roll a 3 . . .

1 . . . 2
or
2 . . . 1

The probability is 3/36 = 1/12 = 0.0833... = (8 and 1/3) percent

You might be interested in

I need help please and thank you

Pachacha [2.7K]

My answers are in the picture above.

8 0

2 years ago

Read 2 more answers

URGENT HELP ME!! <br><br> please no links, thank you<3

Illusion [34]

Answer:

x greater than or equal to 3

x greater than or equal to -8/3

Step-by-step explanation:

3 0

2 years ago

alekssr [168]

Answer: the answer is infinite solutions

Step-by-step explanation:Systems of Equations Level 1:

Question 1

Two linear equations are given below.

Exactly how many solutions does this system of equations have?

Select one:

4 0

2 years ago

The heights of a certain type of tree are approximately normally distributed with a mean height p = 5 ft and a standard

arsen [322]

Answer:

A tree with a height of 6.2 ft is 3 standard deviations above the mean

Step-by-step explanation:

⇒ $1^s^t$ statement: A tree with a height of 5.4 ft is 1 standard deviation below the mean(FALSE)

an X value is found Z standard deviations from the mean mu if:

$\frac{X-\mu}{\sigma} = Z$

In this case we have: $\mu=5\ ft$ $\sigma=0.4\ ft$

We have four different values of X and we must calculate the Z-score for each

For X =5.4\ ft

$Z=\frac{X-\mu}{\sigma}\\Z=\frac{5.4-5}{0.4}=1$

Therefore, A tree with a height of 5.4 ft is 1 standard deviation above the mean.

⇒ $2^n^d$ statement:A tree with a height of 4.6 ft is 1 standard deviation above the mean. (FALSE)

For X =4.6 ft

$Z=\frac{X-\mu}{\sigma}\\Z=\frac{4.6-5}{0.4}=-1$

Therefore, a tree with a height of 4.6 ft is 1 standard deviation below the mean .

⇒ $3^r^d$ statement:A tree with a height of 5.8 ft is 2.5 standard deviations above the mean (FALSE)

For X =5.8 ft

$Z=\frac{X-\mu}{\sigma}\\Z=\frac{5.8-5}{0.4}=2$

Therefore, a tree with a height of 5.8 ft is 2 standard deviation above the mean.

⇒ $4^t^h$ statement:A tree with a height of 6.2 ft is 3 standard deviations above the mean. (TRUE)

For X =6.2\ ft

$Z=\frac{X-\mu}{\sigma}\\Z=\frac{6.2-5}{0.4}=3$

Therefore, a tree with a height of 6.2 ft is 3 standard deviations above the mean.

6 0

2 years ago

I met this hella weird cryptic dude who interviewed me and gave me this puzzle. Solve it within 12 hours and ill let you know wh

Elena-2011 [213]

no cheating thanks <3

6 0

2 years ago