How to solve for x on a quadratic function

1 answer:

7 0

To find the x-intercepts of any equation, substitute 0 in for y and solve for x. So, we have 0 = 3x2+ x + 1. Now, use the quadratic equation to solve for x, wich a = 3, b = 1, and c = 1: So, now we can find the value of the x-intercepts and not have to estimate!

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Combined like terms 11d+8

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2 years ago

The zeros of a function are the values of x x for which the function is equal to zero. Enter a number in each blank to make true

Anit [1.1K]

Answer:

1 or 5

Step-by-step explanation:

Given the function h(x)=(2x−2)(x−5)

The zeros of h(x) are the values of x for which h(x)=0

h(x)=(2x−2)(x−5)=0

Note that if a.b=0, either a=0 or b=0.

Appying the above,

If (2x−2)(x−5)=0

Then:

2x−2=0 or x-5=0

2x=2 or x=5

x=1 0r 5

The zeroes of h(x) as defined are 1 or 5.

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Beaker A contains 1 liter which is 30 percent oil and the rest is vinegar, thoroughly mixed up. Beaker B contains 2 liters which

alekssr [168]

Answer:

1.25 liters of oil

Step-by-step explanation:

Volume in Beaker A = 1 L

Volume of Oil in Beaker A = 1*0.3 = 0.3 L

Volume of Vinegar in Beaker A = 1*0.7 = 0.7 L

Volume in Beaker B = 2 L

Volume of Oil in Beaker B = 2*0.4 = 0.8 L

Volume of Vinegar in Beaker B = 1*0.6 = 1.2 L

If half of the contents of B are poured into A and assuming a homogeneous mixture, the new volumes of oil (Voa) and vinegar (Vva) in beaker A are:

$V_{oa} = 0.3+\frac{0.8}{2} \\V_{oa} = 0.7 \\V_{va} = 0.7+\frac{1.2}{2} \\V_{va} = 1.3$

The amount of oil needed to be added to beaker A in order to produce a mixture which is 60 percent oil (Vomix) is given by:

$0.6*V_{total} = V_{oa} +V_{omix}\\0.6*(V_{va}+V_{oa} +V_{omix}) = V_{oa} +V_{omix}\\0.6*(1.3+0.7+V_{omix})=0.7+V_{omix}\\V_{omix}=\frac{0.5}{0.4} \\V_{omix}=1.25 \ L$