Responder:
1,625; 0.8569
Explicación paso a paso:
y ___0 ____ 1 ____ 2 ____3
P (y) _1 / 8 ___ ¼ ___ ½ ____ 1/8
Valor esperado (E (x)): Σx * p (x)
= (0 * (1/8)) + (1 * (1/4)) + (2 * (1/2)) + (3 * (1/8)) = 1,625
La desviación estándar = sqrt (Var (x))
Var (X) = Σx²p (x) * E (x) ²
Var (X) = [(0 ^ 2 * (1/8)) + (1 ^ 2 * (1/4)) + (2 ^ 2 * (1/2)) + (3 ^ 2 * (1 / 8))] - 1.625²
Var (X) = (0 * (1/8)) + (1 * (1/4)) + (4 * (1/2)) + (9 * (1/8)) - 1.625 ^ 2
= 3.375 - 2.640625
= 0,734375
Desviación estándar = Sqrt (0,734375) = 0,8569
Answer: Larger the MAD tells us that the ages of swimmer are far from the mean age. Thus means is not a relevant indicator for the data.
Step-by-step explanation:
We know that the mean absolute deviation (MAD) helps to know whether the mean of a data is a worthy indicator for the data values .
The larger the MAD tells us the values are spread out far from the mean .
Also, larger the MAD makes the mean less worthy as an indicator of the data elements within the data set.
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Use this equation:
(difference/original) x 100
Substitute in the values:
(150/450) x 100
Solve:
percentage = 33.333
Thus, the answer is option B
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Answer:
6. SAS Postulate
5. ASA Postulate
Step-by-step explanation:
Probably a C-, but it depends on how many other grades are in the gradebook and the exact percentage of your grade.
