Answer:
d = v² / (2μ g)
Explanation:
In the work relationship is equal to the variation of energy,
W = ΔEm
The work is defined by
W = F. d = F d cos θ
In this case the outside is the force of friction, which always opposes
to the movement, so the angle is 180 °
W = - fr d
The force of friction can be found with Newton's second law
fr = μ N
Y Axis
N- W = 0
N = mg
fr = μ m g
We substitute in the expression of work
W = - μ mg d
Now we use the relationship of work and energy
-μ mg d = 0 -½ m v²
d = v² / (2μ g)
(a) If the balloon is suspended in air and it drifts neither up nor down, it means the forces acting on it are equally balanced. There are only two forces acting on the balloon:
- its weight, of magnitude 1 N, directed downward
- the buoyant force, directed upward
The two forces are balanced, so the buoyant force in this case is equal to the weight of the balloon: 1 N.
(b) when the buoyant force decreases, the weight becomes greater than the buoyant force. This means there is now a net force on the balloon, acting downward, so the balloon starts to drift toward the ground.
(c) when the buoyant force increases, it becomes greater than the weight. This means there is now a net force on the balloon, acting upward, so the balloon starts to go up.
Answer:
can u send a picture to identify it
Explanation:
sorry I just need point:/
Answer:
4 blocks west is final displacement. So 4 blocks per hour
Answer:
B. add more loops of wire between the magnets
Explanation:
this would increase the magnetic force acting on the rod therefore increasing
