For the answer to the question above, Tim practices his backhand and his serve at least 2 hours each day this means X =< 2 ( less than or equal to 2 hrs). He works less on his backhand than his serve and practices his serve more than an hour daily. <span>Y < 1</span>
Answer:
C
Step-by-step explanation:
Null hypothesis: hypthesis to test that there is no significant difference between the specific characteristic of a population. Analysts look to reject a null hypothesis
A. the shipping company's average delivery time is different from 3 days. This is an example of alternative hypothesis. Null hypothesis is writtien as a claim
B. This again is an example of alternate hypthesis. The claim that mean is 0.03 is rejected with the results
C. This is a claim
D. This is rejection of a claim that mean is 1 pound
E. This is rejection of claim that average delivery time is 3 days.
Step-by-step explanation:
if 5s=3h
34s=?
we will criss cross and
<u>5sx</u><u>?</u>=<u>3h</u><u>×</u><u>34s</u><u> </u>
<u>5s</u><u> </u> <u>5s</u>
=19.5h
Answer:
I'm going to lay this out in a chart so it's a little easier to see:
F(x) = f(g(x))
x | f (x) | f ' (x) | g (x) | g ' (x)
--------------------------------------
-2 | 8 | 4 |
5 | | 3 | -2 | 6
Remember the chain rule, which says
(f (g (x))) ' = g ' (x) f ' (g (x))
When they ask for F ' (5), they are asking for (f (g (x))) ' when x = 5.
Using the chain rule, that's
F ' (5) = g ' (5) f ' (g (5))
We can simplify using the numbers provided.
F ' (5) = (6) f ' (-2)
F ' (5) = (6) (4)
F ' (5) = 24
I hope that helps!
by jannat <33
Answer:
Step-by-step explanation:
Part 1:
Let
Q₁ = Amount of the drug in the body after the first dose.
Q₂ = 250 mg
As we know that after 12 hours about 4% of the drug is still present in the body.
For Q₂,
we get:
Q₂ = 4% of Q₁ + 250
= (0.04 × 250) + 250
= 10 + 250
= 260 mg
Therefore, after the second dose, 260 mg of the drug is present in the body.
Now, for Q₃ :
We get;
Q₃ = 4% of Q2 + 250
= 0.04 × 260 + 250
= 10.4 + 250
= 260.4
For Q₄,
We get;
Q₄ = 4% of Q₃ + 250
= 0.04 × 260.4 + 250
= 10.416 + 250
= 260.416
Part 2:
To find out how large that amount is, we have to find Q₄₀.
Using the similar pattern
for Q₄₀,
We get;
Q₄₀ = 250 + 250 × (0.04)¹ + 250 × (0.04)² + 250 × (0.04)³⁹
Taking 250 as common;
Q₄₀ = 250 (1 + 0.04 + 0.042 + ⋯ + 0.0439)
= 2501 − 0.04401 − 0.04
Q₄₀ = 260.4167
Hence, The greatest amount of antibiotics in Susan’s body is 260.4167 mg.
Part 3:
From the previous 2 components of the matter, we all know that the best quantity of the antibiotic in Susan's body is regarding 260.4167 mg and it'll occur right once she has taken the last dose. However, we have a tendency to see that already once the fourth dose she had 260.416 mg of the drug in her system, that is simply insignificantly smaller. thus we will say that beginning on the second day of treatment, double every day there'll be regarding 260.416 mg of the antibiotic in her body. Over the course of the subsequent twelve hours {the quantity|the quantity|the number} of the drug can decrease to 4% of the most amount, that is 10.4166 mg. Then the cycle can repeat.
