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2 years ago

How to solve 4(x-3)^2+12=-60

Mathematics

1 answer:

givi [52]2 years ago

6 0

Hope this helps
btw: I used the app photomath so i highly recommend it

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Which of the following uses absolute value correctly to show the distance between −20 and 14?

oee [108]

|-20 - 14| = |-34| = 34 units

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2 years ago

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Help me class8 (surds)

Mashcka [7]

Answer:

$\cfrac{991\sqrt{2} }{80}$

Step-by-step explanation:

For a start simplify each of the roots:

$\sqrt{72} =\sqrt{36*2} =6\sqrt{2}$
$\sqrt{50} =\sqrt{25*2} =5\sqrt{2}$
$\sqrt{128} =\sqrt{64*2} =8\sqrt{2}$
$\sqrt{98} =\sqrt{49*2} =7\sqrt{2}$

Now simplify the expression in steps:

$\sqrt{72}-\cfrac{48}{\sqrt{50} } -\cfrac{45}{\sqrt{128} } +2\sqrt{98} =$

$6\sqrt{2}-\cfrac{48}{5\sqrt{2} } -\cfrac{45}{8\sqrt{2} } +2*7\sqrt{2} =$

$6\sqrt{2}-\cfrac{48*8+45*5}{5*8\sqrt{2} } +14\sqrt{2} =$

$20\sqrt{2}-\cfrac{609}{40\sqrt{2} } =$

$20\sqrt{2}-\cfrac{609*\sqrt{2} }{40\sqrt{2} *\sqrt{2} } =$

$20\sqrt{2}-\cfrac{609\sqrt{2} }{40*2 } =$

$20\sqrt{2}-\cfrac{609\sqrt{2} }{80 } =$

$\sqrt{2} (20-7\cfrac{49}{80} )=$

$\sqrt{2} *12\cfrac{31}{80} =$

$\cfrac{991\sqrt{2} }{80}$

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1 year ago

A practice problem regarding quadrilateral

Vlad [161]

Okay, I’m pretty sire this is right.
A: (-1, 3)
B: (-3, 2)
C: (-8, 3)
D: (-4, 3)

To do this problem (I am not completely confident in this) I am pretty sure you flip the signs for both the x and y values due to the rotation of the shape 180°, then add 6 to the y value.

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2 years ago

How many eggs in 3 and a half dozen?

MariettaO [177]

42.
As
1 dozen is 12 eggs, 3 dozens of the eggs is 12×3=36.
half of a dozens is 6 so
36+6 =42

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2 years ago

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disa [49]

Answer:

1 is a parallelagram