A.) If its booster rockets accelerate the space shuttle at 15m/s2, how high will it be one minute after launch?
1 answer:
You might be interested in
Answer:
Velocity is 1.73 m/s along 54.65° south of east.
Explanation:
Let unknown velocity be v, mass of billiard ball be m and east direction be positive x axis.
Here momentum is conserved.
Initial momentum = Final momentum
Initial momentum = m x 2i + m x (-1)i = m i
Final momentum = m x v + m x 1.41 j = mv + 1.41 m j
Comparing
mi = mv + 1.41 m j
v = i - 1.41 j
Magnitude of velocity
Direction,
Velocity is 1.73 m/s along 54.65° south of east.