<span>Solve the system
9x = 27-9y
20x=71-9y
Let's use the "elimination through addition/subtraction method.
Multiply the first equation by -1 so as to obtain +9y:
-9x = -27 + 9y
</span><span>20x= 71- 9y
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Add these 2 equations together:
</span>-9x = -27 + 9y
20x= 71- 9y
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<span> 11x = 44
Solve this for x: x = 44/11 = 4.
Now find y by subst. 4 for x in either of the original equations.
Using the second equation: </span><span>
</span>20x=71-9y
20(4) = 71 - 9y
80-71 = -9y
9 = -9y. Then y = -1.
The solution set is (4,-1).
Answer:
(x+3)(x+5)<em>(x-2)(x-1)</em><u>(x^2+2x+4)(x^2+x+1)</u> where the given one is bolded the 2 binomials is italicized and the 2 trinomials is underlined
Step-by-step explanation:
D is the answer
(4+8)+1 = 13
4+(8+1) = 13
Therefore equation D is true
