(701+y)/(3+1)<200
(701+y)/4<200
701+y<800
y<99
So the most yards they can allow in the next game is 98 yards
Answer:34.93
Step-by-step explanation:
Using a^2+b^2=c^2we can substitute a and b in which is 34^2+8^2=c^21156+64=c^21220 = c^2Now we need to square both sides√1220 = √c^234.9284983931 ----> 34.9334.93 = cc = 34.93
Sqrt28 = 5.2915~
largest integer below = 5
(round down)
If you multiply -222•10 what is the correct answer?