Answer:
TC (A) = 40x , TC (B) = 500 + 20x
Step-by-step explanation:
Let the number of students be = x
Hall A Total Cost
Relationship Equation, where TC (A) = f (students) = f (x) 40 per person (student) = 40x
Hall B Total Cost
Relationship Equation, where TC (B) = f (students) = f (x) 500 fix fee & 20 per person (student) = 500 + 20x
Answer: 35, 31, 25, 18
Step-by-step explanation:
Answer:
Well u would multiply 20 x 15 to find out the highest if the range which is 300 . So that knocks it down to B or D. But since they're $15 each, It would be based of the multiples of 15 making your answer B .
The range is all the y values.....or the f(x) values .
So the practical range would be the multiples of 15 between 0 and 300,Inclusive .
<h2>Hope this helps you!! </h2>
Answer:
15
Step-by-step explanation:
If CD and DE equal, then x+6 = 4x -21
So if you subtract x from both sides and plus 21 to both sides, that would be 3x = 27. Divide by 3 on both sides and you get 9.
Plug in x+6 with 9 and you get 15.