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2 years ago

10

PLEASE HELP URGENT PLEASE HELP apply the definition of subtraction and properties of operations to find the result. 1/8 - 3/7 -

3/8

1 answer:

Annette [7]2 years ago

8 0

You can make all the denominators equal by multiplying 8 by 7.

That makes it:

7/56 - 24/56 - 21/56 = -38/56 =

-19/28

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Identify the inequality that corresponds to the graph below. Choose all that apply.

mrs_skeptik [129]

The answer is a because it is open circle

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2 years ago

Solve 6x(6x) + 11x - 35 = 0

Murljashka [212]

$36x^2 + 11x - 35=0\\\\ \frac{-b \pm \sqrt{ b^2 -4( a)(c)} }{2(a)}\\\\ \frac{-11\pm \sqrt{11^2 -4(36)(-35)} }{2(36)}\\ \\ \frac{-11\pm \sqrt{5161 } }{72}\\\\\\ x = 0.8450013919812116\\\\ \text{ } x = -1.1505569475367672$

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2 years ago

Read 2 more answers

Elen inwests $100.000 in an account paying 75% interest compounded continuously , How much

Irina18 [472]

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8 0

2 years ago

A soccer player uses her head to hit a ball up in the air from a height of 2 meters with an initial vertical velocity of 5 meter

ozzi

Answer:

The ball will hit the ground in 1.33 s if no one touches it. The equation has 2 real solutions.

Step-by-step explanation:

The ball will hit the ground when its height is equal to 0 meters, therefore using this value in the expression and solving for "t" will give us the correct solutions.

$h = -4.9*t^2 + 5*t + 2\\\\-4.9*t^2 + 5*t + 2 = 0\\\\t_{1,2} = \frac{-5 \pm \sqrt{5^2 - 4*(-4.9)*(2)}}{2*(-4.9)}\\\\t_{1,2} = \frac{-5 \pm \sqrt{64.2}}{-9.8}\\\\t_{1,2} =\frac{-5 \pm 8.0125}{-9.8}\\\\t_1 = \frac{-5 - 8.0125}{-9.8} = 1.33 \text{ s}\\\\t_2 = \frac{-5 + 8.0125}{-9.8} = -0.3 \text{ s}$

The ball will hit the ground in 1.33 s if no one touches it. The equation has 2 real solutions.

8 0

2 years ago

Which of the following is an extraneous solution of the square root of -3x-2=x+2

yarga [219]

Answer:

x=-6 is an extraneous solution

Step-by-step explanation:

we have

$\sqrt{-3x-2} =x+2$

squared both sides

$-3x-2=(x+2)^2$

$-3x-2=x^2+4x+4$

$x^2+7x+6=0$

solve the quadratic equation by graphing

The solution is x=-6 and x=-1

see the attached figure

<u><em>Verify each solution</em></u>

substitute the value of x in the original expression

For x=-6

$\sqrt{-3(-6)-2} =-6+2$

$\sqrt{16} =-4$

$4=-4$ ----> is not true

so

Is an extraneous solution

For x=-1

$\sqrt{-3(-1)-2} =-1+2$

$\sqrt{1} =1$

$1=1$ ----> is true

so

Is the solution

4 0

2 years ago