Write an equation in point-slope form of the line through these given points.I need separate answers for each problem, thx
1 answer:
I like point point form because it doesn't fail in the no slope case. The line through (a,b) and (c,d) is
(c-a)(y-b) = (d-b)(x-a)
Point slope form is almost the same,
1. (a,b)=(4,0),(c,d)=(-2,1)
y - 0 = (1 - 0)/(-2 - 4) (x - 4)
Answer: y = (-1/6)(x-4)
2.
y - -2 = (3 - -2)/(5 - -3) (x - -3)
Answer: y + 2 = (5/8) (x+3)
3.
y - 1 = (4 - 1)/(3 - -5) (x - -5)
Answer: y - 1 = (3/8) (x+5)
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Your inequality looks like this:
To get rid of the /6, you need to multiply by 6 as the opposite operation cancels it out. So, all you need to do is multiply both sides by 6 to isolate x.
Therefore:
To get rid of the /6, you need to multiply by 6 as the opposite operation cancels it out. So, all you need to do is multiply both sides by 6 to isolate x.
Therefore:
Answer:
FD≈25.94.. rounded = 26
Step-by-step explanation:
FD²=12²+(4x+11)²
FD²=144+16x²+88x+121
FD²=265+16x²+88x
also
FD²=12²+(13x-16)²
FD²=144+169x²-416x+256
FD²=400+169x²-416x
thus
265+16x²+88x = 400+169x²-416x
16x²-169x²+88x+416x+265-400 = 0
-153x²+504x-135 = 0
we will solve this quadratic equation by suing the quadratic formula to find x
x=(-504±sqrt(504²-4(-153)(-135)))/2(-153)
x=(-504±)/2(-153)
x=(-504±)/-306
x=(-504±)/-306
x=(-504±414)/-306
x=(-504+414)/-306 and x=(-504-414)/-306
x=-90/-306 and x=-918/-306
x= 5/17 , 3
substituting x by the roots we found
check for 5/17:
4x+11 = 4×(5/17)+11 = (20/17)+11 = (20+187)/17 = 207/17 ≈ 12.17..
13x-16 = 13×(5/17)-16 = (65/17)-16 = (65-272)/17 = -207/17 ≈ -12.17..
check for 3:
4x+11 = 4×3+11 = 12+11 = 23
13x-16 = 13×3-16 = 23
thus 3 is the right root
therfore
ED=23 and CD=23
FD²=FE²+ED² or FD²=FC²+CD²
FD²=12²+23²
FD²=144+529
FD²=673
FD=√673
FD≈25.94.. rounded = 26