Answer:
14.63% probability that a student scores between 82 and 90
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What is the probability that a student scores between 82 and 90?
This is the pvalue of Z when X = 90 subtracted by the pvalue of Z when X = 82. So
X = 90
has a pvalue of 0.9649
X = 82
has a pvalue of 0.8186
0.9649 - 0.8186 = 0.1463
14.63% probability that a student scores between 82 and 90
Answer:
answer is 3
Step-by-step explanation:
n+1=3+2/2=3
The number is 3 and it is a odd number.
I hope it's helpful!
I got x is less than or equal to -3/2
Answer: ∠A = 70°
because ABC is an isosceles triangle and AB = AC
=> ∠B = ∠C = 55°
=> ∠A = 180-(∠B + ∠C) = 180° - 55°.2 = 70°
Step-by-step explanation:
Answer:
a) 1 game
b) 41 goals
c) median = 2
Step-by-step explanation:
a)
As we can see in the line graph, where we have the 0 for the number of goals scored, the graph indicates only 1 in the number of games, so we have only 1 game where no goals were scored.
b)
To find the total number of goals scored, we multiply the goals scored by the number of games for that score, and then sum them all:
total goals = 1*0 + 4*1 + 5*2 + 6*3 + 1*4 + 1*5 = 41 goals
c)
To find the median, we put all the goals in crescent order, and then find the value in the middle. As we have 18 games, the middle value will be an average of the 9th and 10th terms.
We have 1 number 0, 4 numbers 1 and 5 numbers 2 in the beginning, so for these 10 numbers, the 9th and the 10th are the score 2, so the median is 2.