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2 years ago

Write three million five hundred twenty six thousand two hundred forty five in standard form

2 answers:

7 0

Standard form: 3,526,245

Expanded form: 3,000,000 + 500,000 + 20,000 + 6,000 + 200 + 40 + 5

You've already written it in word form :)

Hope this helps!

Temka [501]2 years ago

3 0

3,526,245 is the answer.

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Solve the equation algebraically |x|=12

sergiy2304 [10]

Answer:

x = 12

Step-by-step explanation:

Absolute value is the distance between the number and 0. Since distance cannot be negative, the absolute value of something is always going to be positive. In this equation | x | = 12 since 12 is already a postive number and the distance between 12 and 0 is 12, this means that x is equal to 12.

Hope This Helps :)

4 0

2 years ago

To factor a<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" align="absmiddle" class="la

Ivan

Answer:

I'm not sure. Try asking Google.

Plzzzzz give me Brainliest!!!!!

4 0

2 years ago

Read 2 more answers

Use the drop-down menus to complete each equation so the statement about its solution is true?

SashulF [63]

5 - 4 + 7x + 1 = 7x + (5 - 4 + 1) = 7x + 2

NO SOLUTIONS:

5 - 4 + 7x + 1 = 7x + a (a - any real number, except 2)

ONE SOLUTION:

5 - 4 + 7x + 1 = bx + c (b - any real number, except 7, c - any real number)

INFINITELY MANY SOLUTIONS:

5 - 4 + 7x + 1 = 7x + 2

Examples:

2x + 3 = 2x + 5 subtract 2x from both sides

3 = 5 FALSE (NO SOLUTIONS)

2x + 3 = x - 4 subtract x from both sides

x + 3 = -4 subtract 3 from both sides

x = -7 (ONE SOLUTION)

2x + 3 = 2x + 3 subtract 2x from both sides

3 = 3 TRUE (INFINITELY MANY SOLUTIONS)

7 0

2 years ago

Identify the hypothesis and conclusion of each conditional statement. Then write each sentence in if-then form

lukranit [14]

Answer:

If you place two collinear points, then they will fall on the same line

Step-by-step explanation:

3 0

2 years ago

What is the first step in solving this system of equations by elimination? 5a + 3b = –9 2a – 5b = –16

Elis [28]

Multiply one of the equations so that both equations share a common complementary coefficient.
In order to solve using the elimination method, you need to have a matching coefficient that will cancel out a variable when you add the equations together. For the 2 equations given, you have a huge number of choices. I'll just mention a few of them.
You can multiply the 1st equation by -2/5 to allow cancelling the a term.
You can multiply the 1st equation by 5/3 to allow cancelling the b term.
You can multiply the 2nd equation by -2.5 to allow cancelling the a term. You can multiply the 2nd equation by 3/5 to allow cancelling the b term.
You can even multiply both equations.
For instance, multiply the 1st equation by 5 and the second by 3. And in fact, let's do that. 5a + 3b = â€“9 2a â€“ 5b = â€“16 5*(5a + 3b = -9) = 25a + 15b = -45
3*(2a - 5b = -16) = 6a - 15b = -48
Then add the equations 25a + 15b = -45
6a - 15b = -48
=
31a = -93
a = -3
And then plug in the discovered value of a into one of the original equations and solve for b.

5 0

2 years ago