Write the ratios for sin X, cos X,and tan X

Can somebody help me do this, please

natta225 [31]

Step-by-step explanation:

For the triangle on the bottom right the missing angle is

180- (74+50)= 56°

For the triangle on the bottom left the missing angle is

180- (45+80)= 55°

For the triangle in the middle the missing angle is

180- (54+51)= 75°

For the triangle on top the missing angle is

180- (80+54)= 46°

180- (74+51)= 55°

180- (46+55)= 79°

3 0

2 years ago

Can u explain part B. Please

Marizza181 [45]

I don't understand what you're asking, is there supposed to be a picture with the question?

5 0

2 years ago

Y=x+2 2x-y=-4 Solve the systems of equations

larisa86 [58]

Answer:

Step-by-step explanation:

Given that,

y=x+2 equation 1

2x-y=-4 equation 2

This is a simultaneous equation.

Substitute equation 1 into equation 2

2x-y=-4. Since y=x+2

2x-(x+2) = -4

2x-x-2 = -4

x-2 = -4

x = -4+2

x = -2

Also from equation 1

y=x+2

Since x=-2

y=-2+2

y=0

Then, solution (x, y) = (-2,0)

4 0

2 years ago

Read 2 more answers

Assuming that one-pint is equal to 473 ml, how many pints can be found in 3 liters?

Svetlanka [38]

Given that 1 pint is equal to 437 ml
and 1000 ml=1 liter
then
1 pint =(437/1000) liters
simplifying we get:
1 pint= 0.437 liters
thus amount of pints in 4 liters will be:
4/0.473
=8.45666586
~8.5 pints

4 0

2 years ago

What are the solutions of the equation 9x4 – 2x2 – 7 = 0? Use u substitution to solve. tions of the equation 9

skelet666 [1.2K]

Answer:

Step-by-step explanation:

Let $u^2=x^4\\u = x^2$

Subbing in:

$9u^2-2u-7=0$

a = 9, b = -2, c = -7

The product of a and c is the aboslute value of -63, so a*c = 63. We need 2 factors of 63 that will add to give us -2. The factors of 63 are {1, 63}, (3, 21}, {7, 9}. It looks like the combination of -9 and +7 will work because -9 + 7 = -2. Plug in accordingly:

$9u^2-9u+7u-7=0$

Group together in groups of 2:

$(9u^2-9u)+(7u-7)=0$

Now factor out what's common within each set of parenthesis:

$9u(u-1)+7(u-1)=0$

We know this combination "works" because the terms inside the parenthesis are identical. We can now factor those out and what's left goes together in another set of parenthesis:

$(u-1)(9u+7)=0$

Remember that $u=x^2$

so we sub back in and continue to factor. This was originally a fourth degree polynomial; that means we have 4 solutions.

$(x^2-1)(9x^2+7)=0$

The first two solutions are found withing the first set of parenthesis and the second two are found in other set of parenthesis. Factoring $(x^2-1)$ gives us that x = 1 and -1. The other set is a bit more tricky. If