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sertanlavr [38]

3 years ago

7

The Drama Club is showing a video of their recent play.The first showing begin at 2:30pm.The second showing is scheduled at 5:25

pm. with a 1/2hours break between the showings

1 answer:

zavuch27 [327]3 years ago

5 0

Each showing is 145 minutes.

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Pls help for brainlist

snow_tiger [21]

Answer: 7/20

Step-by-step explanation:

3/4 - 2/5

= 3x5/4x5 - 2x4/5x4

=15/20 - 8/20

= 7/20

Hope it helped u,

pls mark as the brainliest

^_^

3 0

2 years ago

Read 2 more answers

Which number has a 5 that represents a value ten times greater than the value

amm1812

It would be 42,523 because 50x10=500 and 5 in 42,523 is in the hundreds spot

8 0

2 years ago

Plz ans asap i havd limited time ill give brainliest

Artemon [7]

Answer:

C. $128

Step-by-step explanation:

320 x 0.5 = 160

320 - 160 = 160

160 x 0.20 = 32

160 - 32 = 128

5 0

2 years ago

Read 2 more answers

I got a tricky one

Yuliya22 [10]

Answer:

D. f(-3) = 11

Step-by-step explanation:

When f(x) is divided by x+3, you get a quotient g(x) and a remainder of 11:

f(x) / (x + 3) = g(x) + 11 / (x + 3)

Multiply both sides by x+3:

f(x) = g(x) (x + 3) + 11

Substitute -3 for x:

f(-3) = g(-3) (-3 + 3) + 11

f(-3) = g(-3) (0) + 11

f(-3) = 11

4 0

2 years ago

The fraction of defective integrated circuits produced in a photolithography process is being studied. A random sample of 300 ci

Olenka [21]

Answer:

The correct answer is

(0.0128, 0.0532)

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence interval $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

Z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$

For this problem, we have that:

In a random sample of 300 circuits, 10 are defective. This means that $n = 300$ and $\pi = \frac{10}{300} = 0.033$

Calculate a 95% two-sided confidence interval on the fraction of defective circuits produced by this particular tool.

So $\alpha$ = 0.05, z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{300}} = 0.033 - 1.96\sqrt{\frac{0.033*0.967}{300}} = 0.0128$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{300}} = 0.033 + 1.96\sqrt{\frac{0.033*0.967}{300}} = 0.0532$

The correct answer is

(0.0128, 0.0532)

4 0

2 years ago