Answer:
The area of an octagon whose perimeter is 120 cm is 1086.4
Step-by-step explanation:
An octagon is a polygon with eight sides. If the lengths of all the sides and the measurement of all the angles are equal, the octagon is called a regular octagon.
There is a predefined set of formulas for the calculation of perimeter, and area of a regular octagon.
The perimeter of an Octagon is given by
and the area of an Octagon is given by
We know that the perimeter is 120 cm, solving for side length (a) in the perimeter formula we get
Now, we calculate the area
Answer:
{x,y,z} = {-18,4,2}
Step-by-step explanation:
Solve equation [2] for the variable x
x = -10y + 2z + 18
Plug this in for variable x in equation [1]
(-10y+2z+18) + 9y + z = 20
- y + 3z = 2
Plug this in for variable x in equation [3]
3•(-10y+2z+18) + 27y + 2z = 58
- 3y + 8z = 4
Solve equation [1] for the variable y
y = 3z - 2
Plug this in for variable y in equation [3]
- 3•(3z-2) + 8z = 4
- z = -2
Solve equation [3] for the variable z
z = 2
By now we know this much :
x = -10y+2z+18
y = 3z-2
z = 2
Use the z value to solve for y
y = 3(2)-2 = 4
Use the y and z values to solve for x
x = -10(4)+2(2)+18 = -18
Answer: 56 / 729
Step-by-step explanation: (4 * 2 * 7) / (9^3)
Answer:
x = 6
Step-by-step explanation:
r = 6 sec θ
r = 6 / cos θ
r cos θ = 6
x = 6
The graph is a vertical line passing through (6, 0).
If u wrote 9 to the power of - 2 and x to the power of - 1 and y to the power of 0 and write the x at then end it would end up a fraction of 1/81 but I'm not sure what u want like multiply?