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2 years ago

ANSWER ASAP AND I WILL GIVE BRAINLYEST!!!!

Chemistry

2 answers:

rusak2 [61]2 years ago

5 0

Answer:

oceans transfer energy from the sun. They do so , in order to exchange heat and moisture to the sky and earth influencing weather systems accordingly.

The ocean influences weather patterns by distributing heat and moisture around the globe. ... Tropical storms form over warm ocean waters, which supply the energy for hurricanes and typhoons to grow and move, often over land. The winter storms that bring precipitation to the western U.S. originate over the North Pacific.

inysia [295]2 years ago

3 0

Ocean currents act much like a conveyor belt, transporting warm water and precipitation from the equator toward the poles and cold water from the poles back to the tropics. Thus, ocean currents regulate global climate, helping to counteract the uneven distribution of solar radiation reaching Earth's surface. I think its B

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The standard cell potential (E°cell) for the reaction below is +0.63 V. The cell potential for this reaction is ________ V when

tia_tia [17]

Answer : The cell potential for this reaction is 0.50 V

Explanation :

The given cell reactions is:

$Pb^{2+}(aq)+Zn(s)\rightarrow Zn^{2+}(aq)+Pb(s)$

The half-cell reactions are:

Oxidation half reaction (anode): $Zn\rightarrow Zn^{2+}+2e^-$

Reduction half reaction (cathode): $Pb^{2+}+2e^-\rightarrow Pb$

First we have to calculate the cell potential for this reaction.

Using Nernest equation :

$E_{cell}=E^o_{cell}-\frac{2.303RT}{nF}\log \frac{[Zn^{2+}]}{[Pb^{2+}]}$

where,

F = Faraday constant = 96500 C

R = gas constant = 8.314 J/mol.K

T = room temperature = $25^oC=273+25=298K$

n = number of electrons in oxidation-reduction reaction = 2

$E^o_{cell}$ = standard electrode potential of the cell = +0.63 V

$E_{cell}$ = cell potential for the reaction = ?

$[Zn^{2+}]$ = 3.5 M

$[Pb^{2+}]$ = $2.0\times 10^{-4}M$

Now put all the given values in the above equation, we get:

$E_{cell}=(+0.63)-\frac{2.303\times (8.314)\times (298)}{2\times 96500}\log \frac{3.5}{2.0\times 10^{-4}}$

$E_{cell}=0.50V$

Therefore, the cell potential for this reaction is 0.50 V

5 0

2 years ago

Red aesthetic and one other thing

Katena32 [7]

I was on the phone to see if you wanted me a couple questions and I would be able answer questions on how

5 0

2 years ago

Read 2 more answers

You operate a nuclear reactors and want to use fissionable mass that will sustain a slow control what type of mass will you use

puteri [66]

Answer: I believe it is critical mass

Explanation:

3 0

1 year ago

The ion MnOis often used to analyze for the Fe2+ content of an aqueous solution by using the (unbalanced) reaction Mno+Fe2+ + Fe

dusya [7]

Answer:

B) 0.230 M

Explanation:

The first step is to balance the reaction between the Ferrous ion and the permanganate ion:

$5~Fe^+^2~+~MnO_4^-^1~+~8H^+~->~5Fe^+^3~+~Mn^+^2~+4H_2O$

Then we have to calculate the moles of $MnO_4^-$ :

$M~=~\frac{mol}{L}$

$mol~=~M*L$

$mol~=~0.033~M*0.0633L=~0.002088~mol~MnO_4^-$

Then using the molar ratio we can find the moles of $Fe^+^2$ :

$0.002088~mol~MnO_4^-\frac{5~mol~Fe^+^2}{1~mol~MnO_4^-}=0.01044~mol~Fe^+^2$

Finally we can calculate the molarity:

$M=\frac{0.01044~mol~Fe^+^2}{0.0455~L}=0.230~M$

5 0

2 years ago

What evidence supports a conservation law?

True [87]

Answer:

The answer is B.

Explanation:

The law of conservation of mass states that mass in an isolated system is neither created nor destroyed by chemical reactions or physical transformations.

According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.

The law of conservation of mass is useful for a number of calculations and can be used to solve for unknown masses, such the amount of gas consumed or produced during a reaction.

3 0

2 years ago