Step-by-step explanation: (8,5)(-12,-9)slope = (-9 - 5) / (-12 - 8) = -14/-20 = 7/10y = mx + bslope(m) = 7/10use either of ur points.....(8,5)....x = 8 and y = 5now we sub and find b, the y int5 = 7/10(8) + b5 = 56/10 + b5 - 56/10 = b50/10 - 56/10 = b-3/5 = bso ur equation is : y = 7/10x - 3/5.....now we put it in standard formy = 7/10x - 3/5...multiply by 1010y = 7x - 6.....subtract 7x-7x + 10y = -6....multiply by -17x - 10y = 6So.....7x - 10y = 3.... IS NOT a good model. Because ur points are not a solution to ur equation.
y = mx + b slope(m) = 7/10 use either of ur points.....(8,5)....x = 8 and y = 5 now we sub and find b, the y int 5 = 7/10(8) + b 5 = 56/10 + b 5 - 56/10 = b 50/10 - 56/10 = b -3/5 = b
so ur equation is : y = 7/10x - 3/5.....now we put it in standard form
y = 7/10x - 3/5...multiply by 10 10y = 7x - 6.....subtract 7x -7x + 10y = -6....multiply by -1 7x - 10y = 6
So.....7x - 10y = 3.... IS NOT a good model. Because ur points are not a solution to ur equation.
Her statement is possible, the first rectangle could be equal to the second because x is unknown so if x was 5in in the first rectangle and - 1 in the second rectangle both problems would look like this 2 in & 5 in and the second one 5in & (2 in = (-1 +3)).