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2 years ago

What is the interquartile range(IQR) of the data set represented by this box plot?

Mathematics

2 answers:

Oksana_A [137]2 years ago

6 0

Answer:

Answer:22

Step-by-step explanation:

Nesterboy [21]2 years ago

5 0

IQR=Q3-Q1
73-51=22
Answer:22

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1+1 then divide by 8

Gemiola [76]

Answer:

0.25

Step-by-step explanation:

4 0

2 years ago

A filter filled with liquid is in the shape of a vertex-down cone with a height of 9 inches and a diameter of 6 inches at its op

Alina [70]

Answer: Level of the liquid dropping at 28.28 inch/second when the liquid is 2 inches deep.

Step-by-step explanation:

Since we have given that

Height = 9 inches

Diameter = 6 inches

Radius = 3 inches

So, $\dfrac{r}{h}=\dfrac{3}{9}=\dfrac{1}{3}\\\\r=\dfrac{1}{3}h$

Volume of cone is given by

$V=\dfrac{1}{3}\pi r^2h\\\\V=\dfrac{1}{3}\pi \dfrac{1}{9}h^2\times h\\\\V=\dfrac{1}{27}\pi h^3$

By differentiating with respect to time t, we get that

$\dfrac{dv}{dt}=\dfrac{1}{27}\pi \times 3\times h^2\dfrac{dh}{dt}=\dfrac{1}{9}\pi h^2\dfrac{dh}{dt}$

Now, the liquid drips out the bottom of the filter at the constant rate of 4 cubic inches per second, ie $\dfrac{dv}{dt}=-4\ in^3$

and h = 2 inches deep.

$-4=\dfrac{1}{9}\times \pi\times (2)^2\dfrac{dh}{dt}\\\\-9\pi =\dfrac{dh}{dt}\\\\-28.28=\dfrac{dh}{dt}$

Hence, level of the liquid dropping at 28.28 inch/second when the liquid is 2 inches deep.

7 0

2 years ago

14,779 107,033 123,737 round to the nearest hundred?

denpristay [2]

Step-by-step explanation:

14,800

107

123,700

hope this helps have a great day

3 0

2 years ago

F(1) = 5

MatroZZZ [7]

Answer:

a(7)=3645

Step-by-step explanation:

you have :

f(1) =a= 5

and from recursive rule: f(n) = r · f(n − 1) and f(n) = 3 · f(n − 1)

So r=3

then

a(n)=a*r^(n-1)

a(7)=5*3^(7-1)

a(7)=5*3^6=3645

<em>hope this helps</em>

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7 0

2 years ago

What is 48% written as a fraction? (in simplest form) A) 1 48 B) 6 25 C) 12 25 D) 24 25

alexgriva [62]

Answer:

48% is 12/25 as a fraction. So C

3 0

2 years ago