She could switch them around by grouping them into groups of 4s, 3s, 2s, or 5s.
Answer:
22222222222222222 not 3 and not 1
Step-by-step explanation:
Answer:
<em>(</em><em>2</em><em>x</em><em> </em><em>+</em><em> </em><em>1</em><em>)</em><em> </em><em> </em><em>(</em><em>3</em><em>x</em><em> </em><em>-</em><em> </em><em>4</em><em>)</em>
Step-by-step explanation:
Solution:
- 6x² - 5x - 4
- 6x²- (8 - 3)x - 4
- 6x²- 8x + 3x - 4
- 2x (3x - 4) +1 (3x - 4)
- (2x + 1) (3x - 4)
Answer:
D) q + d = 330
0.25q + 0.1d = 6
Step-by-step explanation:
Let q= numbers of quarters
d = number of dimes
q + d = 33 ...........(1)
q = 33 - d
xq + yd = 6 ..........(2)
We will consider the options to know the correct answer
From option A
q +d = 6
25q + 10d = 33
This is wrong
Option B
q + d = 60
0.25q + 0.1d = 33
This is also wrong
Option C
q+d = 33
25q + 10d = 6
Put q = 33 -d in equation 2
25(33 - d) + 10q = 6
825 - 25d + 10d = 6
825 - 15d = 6
-15d = 6-825
-15d = -819
d = -819/-15
d= 54.6
This is also wrong because d exceeds the combination.
Option D
q+d = 33
0.25q + 0.1d = 6
Put q = 33 -d in equation 2
0.25(33 - d) + 0.1d = 6
8.25 - 0.25d + 0.1d = 6
8.25 - 0.15d = 6
-0.15d = 6 - 8.25
-0.15d = -2.25
d = -2.25/ -0.15
d = 15
q = 33 - 15
q = 18
This is correct
If x = 3 and y =2 then 8x+7y= 38
and 2y = 4x is correct
hope it helps :)
edit i was incorrect about second answer it would be
2y =4x-4
