H = –16t2 + 156t + 105, when t = t', the time where the rocket hit the ground after it is launched, so 105= –16t'2 + 156t' + 105, so -16t'2 + 156t' = 0 implies t' =0 or -16t'+ 156= 0, equivalent to t'=9.75, so the answer is
b) <span>9.8 s</span>
Answer:
Step-by-step explanation:
<u>Table P
</u>
- Not a function as repeat input of 6 with different outputs
<u>Table Q
</u>
- Not a function as repeat input of 5 with different outputs
<u>Table R
</u>
<u>Table S</u>
- Not a function as repeat input of 4 with different outputs
Parallel have same slope
Perpendicular have opposite reciprocal slopes. Ex. 2/3 is slope of one line so the perpendicular line would have slope of -3/2.
Find slopes of these lines.
-4x-5y=-4
-4x+4 =5y
Divide by 5
Y= -4x/5 +4/5
Second line: 10x-8y=-1
10x+1=8y
Divide by 8
10x/8 +1/8 =y
Y= 5x/4 +1/8
So if you look at slope of line 1= -4/5 and line 2 it’s 5/4 so these both are perpendicular.
Multiply the numbers being added then add the first number. 4X1=4, 4+1=5.
2X5=10, 10+2=12. 11X8=88, 88+8=96. I'm not sure how to get 40, though.
Hope I could help.
Answer:
x=43
Step-by-step explanation:
Since the lines are parrallel, the angle underneath the one you are finding is equal to 65. To find the total value of (x+72) you subtract 65 from 180, giving you 115.
x+72 = 115
then you subtract 72 from both sides
x=43