The sides of a rectangle are in a 3:4 ratio. What is the length of the shorter sides of the rectangle if its perimeter is 42 cm?

Mathematics

1 answer:

Alisiya [41]2 years ago

6 0

The shorter sides together equal 10.5, but each one is 5.25

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SOMEONE PLEASE JUST ANSWER THIS FOR BRAINLIEST!!!

Sloan [31]

ANSWER

$P-G = 11{w}^{4} - 5 {w}^{2} {z}^{2} - 4z^{4}$

EXPLANATION

The given polynomials are:

$G = - 3 {w}^{4} + 2 {w}^{2} {z}^{2} + 5z^{4}$

and

$P = 8 {w}^{4} - 3{w}^{2} {z}^{2} + z^{4}$

We want to subtract these two polynomials.

$P-G = 8 {w}^{4} - 3{w}^{2} {z}^{2} + z^{4} - (- 3 {w}^{4} + 2 {w}^{2} {z}^{2} + 5z^{4} )$

Expand the right hand side to obtain:

$P-G = 8 {w}^{4} - 3{w}^{2} {z}^{2} + z^{4} + 3 {w}^{4} - 2 {w}^{2} {z}^{2} - 5z^{4}$

Group the similar terms:

$P-G = 8 {w}^{4} + 3 {w}^{4}- 3{w}^{2} {z}^{2} - 2 {w}^{2} {z}^{2} - 5z^{4} + z^{4}$

Combine the similar terms to get:

$P-G = 11{w}^{4} - 5 {w}^{2} {z}^{2} - 4z^{4}$

7 0

2 years ago

The half-life of a certain radioactive material is 78 hours. An initial amount of the material has a mass of 790 kg.. Write an e

adoni [48]

<span> half life i= 78 hours
amount after 78 hours is 395 kg:
395 = 790e^(k*78)

Dividing by 790 and taking natural log
ln (395/790) = (k*78)
-0.6931 = 78k
-0.00888 = k

lets calculate how much is left after 18 hours:
Amount(18)
= 790e^(-0.00888*18)
Amount = 673.301 kg
hope this helps</span>

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2 years ago

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sergey [27]

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2 years ago

Solve question please

JulijaS [17]

Answer:

289

Step-by-step explanation:

$17^{2}$