A 34n force is applied to a 213kg mass how much does the mass accelerate
1 answer:
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Data:
h = 2m
m = 45 Kg
PE = ? (Joule)
Adopting, gravity (g) ≈ <span>9,8 m/s²
</span>
Formula:
Solving:
Answer:
<span>The sled's potential energy is 882 Joules</span>
h = 2m
m = 45 Kg
PE = ? (Joule)
Adopting, gravity (g) ≈ <span>9,8 m/s²
</span>
Formula:
Solving:
Answer:
<span>The sled's potential energy is 882 Joules</span>
Answer:
Explanation:
a ) Slit separation d = .1 x 10⁻³ m
Screen distance D = 4 m
wave length of light λ = 650 x 10⁻⁹ m
Width of central fringe = λ D / d
=
= 26 mm
b ) Distance between 1 st and 2 nd bright fringe will be equal to width of dark fringe which will also be equal to 26 mm
c ) Angular separation between the central maximum and 1 st order maximum will be equal to angular width of fringe which is equal to
λ / d
=
= 6.5 x 10⁻³ radian.