Answer:
w=5h-8
Step-by-step explanation:
Take the original formula h=(1/5)w+(8/5)
Subtract -8/5 on both sides to isolate the w, so h-8/5=(1/5)w
Now you have to get rid of the 1/5, so multiply 5(h-8/5), the 5 in the 8/5 cross each other out. You are left with 5h-8
Might have to experiment a bit to choose the right answer.
In A, the first term is 456 and the common difference is 10. Each time we have a new term, the next one is the same except that 10 is added.
Suppose n were 1000. Then we'd have 456 + (1000)(10) = 10456
In B, the first term is 5 and the common ratio is 3. From 5 we get 15 by mult. 5 by 3. Similarly, from 135 we get 405 by mult. 135 by 3. This is a geom. series with first term 5 and common ratio 3. a_n = a_0*(3)^(n-1).
So if n were to reach 1000, the 1000th term would be 5*3^999, which is a very large number, certainly more than the 10456 you'd reach in A, above.
Can you now examine C and D in the same manner, and then choose the greatest final value? Safe to continue using n = 1000.
*see attachment for the figure referred to
Answer/Step-by-step explanation:
1. PN = 29
MN = 13
PM = ?
(Segment addition postulate)
(subtract MN from each side)
(substitute)
2. PN = 34, MN = 19, PM = ?
(sediment addition postulate)
(subtract MN from each side)
(substitute)
3. PM = 19, MN = 23, PN = ?
(Segment addition postulate)
(substitute)
4. MN = 82, PN = 105, PM = ?
(segment addition postulate)
(subtract MN from each side)
(substitute)
5. PM = 100, MN = 100, PN = ?
(Segment addition postulate)
(substitute)
