<span>z2-z(z+3)+3z
=> z2 - z2 - 3z + 3z
=> 0
we can cancel the like terms if they have different signs ..
Hope it helps !!</span>
Answer:5/12 (Decimal: 0.416667)
Step-by-step explanation:
You can write this two ways - as a list of prime factors, or combine like factors and represent their quantity with an exponent.
If you begin by dividing by two, you can do that six times, with a three as the remaining prime factor.
2·2·2·2·2·2·3
OR
2∧6 · 3
Answer:
Step-by-step explanation:
You don't specify what you're supposed to do, so I'll make an educated guess.
Given the sequence f(1) = 4, f(n) = f(n − 1) + 11, find the first 5 terms:
f(1) = 4
f(2) = f(2 - 1) + 11 = f(1) + 11 = 4 + 11 = 15
f(3) = f(2) + 11 = 15 + 11 = 26
f(4) = f(3) + 11 = 26 + 11 = 37
f(5) = 37 + 11 = 48
Answer:
Step-by-step explanation:
7y+5+3y+5=70
10y+10=70
10y=60
y=6
7(6)+5= 42+5= 47
3(6)+5= 18 + 5 =23
47+23= 70
