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2 years ago

13

Photographs of many young stars show long jets of material apparently being ejected from their poles.

1 answer:

Rudiy272 years ago

7 0

Answer:

A) True

Explanation:

Researchers have detected numerous jets of gas ejected from poles of young stars and planetary nebulae.

By examining images of hydrogen molecules excited at infrared wavelengths, scientists have been able to see through the gas and dust in the Milky Way, in order to observe the most distant targets. These goals are normally hidden from view and many of them have never been seen before.

The entire study area covers approximately 1,450 times the size of the full moon, or the equivalent of an image of 95 gigapixels. The survey reveals jets emanating from proto-stars and planetary nebulas, as well as remnants of supernovae, the illuminated edges of vast clouds of gas and dust, and the warm regions that surround massive stars and their associated groups of smaller stars.

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Which of the following would decrease your carbon footprint?

salantis [7]

The third option seems correct. Using any bag more than once will help in decreasing the carbon foot print.

This isds beause, if you use paper bag once only, then paper bag is being utilised and more and more paper is being used. So the best way is to use the bag more than once, whichever bag u are using.

7 0

2 years ago

Read 2 more answers

Henrietta is going off to her physics class, jogging down the sidewalk at a speed of 2.70 m/s. Her husband Bruce suddenly realiz

Katen [24]

Answer:

The velocity is $v = 6.66 \ m/s$

Henrietta is at distance $s= 18.17 \ m$ from the under the window

Explanation:

From the question we are told that

The speed of Henrietta is $v= 2.70 \ m/s$

The height of the window from the ground is $h = 36.5 \ m$

Generally the time taken for the lunch to reach the ground assuming it fell directly under the window is

$t = \sqrt{\frac{2 * h }{g} }$

=> $t = \sqrt{\frac{2 * 36.5 }{9,8} }$

=> $t = 2.73 \ s$

Generally the time taken for the lunch to reach Henrietta is mathematically represented as

$T = t + t_1$

Here $t_1$ is the time duration that elapsed after Henrietta has passed below the window the value is given as 4 s

Now

$T = 2.73 + 4$

=> $T = 6.73 \ s$

Generally the distance covered by Henrietta before catching her lunch is

$s= v * T$

=> $s= 2.70 * 6.73$

=> $s= 18.17 \ m$

Generally the speed with which Bruce threw her lunch is mathematically represented as

$v = \frac{18.17}{2.73}$

$v = 6.66 \ m/s$

4 0

2 years ago

Solve the question that follows using the equation for the conversion of Celsius to Fahrenheit. F=95(C)+32 On February 9, 1934,

SVEN [57.7K]

Answer:

Buffalo, NY

Explanation:

Temperature in Buffalo, NY = -29°C

In order to compare the temperatures we need to convert them to the same scale.

$F=\dfrac{9}{5}C+32\\\Rightarrow F=\dfrac{9}{5}\times -29+32\\\Rightarrow F=-20.2$

So, the temperature in Buffalo, NY was -20.2°F and the temperature in Anchorage, AL was 19°F.

Hence, it was colder in Buffalo, NY than in Anchorage, AL.

3 0

2 years ago

An ice skater wins a competition. Flowers are thrown on the ice rink to celebrate. The ice skater picks up a 0.3

Serga [27]

Answer:

i speak english

Explanation:

3 0

1 year ago

Suppose a wheel with a tire mounted on it is rotating at the constant rate of 2.23 2.23 times a second. A tack is stuck in the t

elena-14-01-66 [18.8K]

Explanation:

The given data is as follows.

Angular velocity ( $\omega$ ) = 2.23 rps

Distance from the center (R) = 0.379 m

First, we will convert revolutions per second into radian per second as follows.

= 2.23 revolutions per second

= $2.23 \times 2 \times 3.14 rad/s$

= 14.01 rad/s

Now, tangential speed will be calculated as follows.

Tangential speed, v = $R \times \omega$

= 0.379 x 14.01

= 5.31 m/s

Thus, we can conclude that the tack's tangential speed is 5.31 m/s.

8 0

2 years ago