Answer:
Explanation:
c )
First of all we shall calculate the velocity of bullet just after the collision with the pendulum by applying conservation of momentum law.
v₂ = mv₁ / ( m + M )
v₂ is velocity after the collision , m is mass of bullet v₁ is velocity of bullet and M is mass of pendulum.
v₂ = .030 x 185 / 3.18
= 1.745 m /s
Let the angle of the pendulum’s maximum displacement with the vertical be θ
height attained by the pendulum h = L ( 1 - cosθ) ; L is the length of the string.
Applying conservation of mechanical energy law
mgh = 1/2 m v₂²
m is mass of (bullet+ pendulum) , v₂ is its velocity
g L ( 1 - cosθ) = v₂² / 2
9.8 x 2.85 ( 1 - cosθ) = 1.745² / 2
( 1 - cosθ) = .0545
cosθ = .9455
θ = 19 degree
a ) The vertical component of the pendulum’s maximum displacement.
L ( 1 - cosθ)
= 2.85 ( 1 - .9455
= .155 m
b ) Horizontal component : L sin18
= 3.15 x .30
= .97 m .
