so we know that 24% of the students buy their lunch at the cafeteria, and 190 students brownbag.
well, 100% - 24% = 76%, so the remainder of the students, the one that is not part of the 24% is 76%, and we know that's 190 of them.
since 190 is 76%, how much is the 24%?
Answer:
Step-by-step explanation:
The record of the statistics and the summary statistics which are the missing files in the question are attached below.
From the given information:
The null hypothesis and the alternative hypothesis can be represented by :
There is no difference between the average time spend by men and women at gym each week
The average time spend by men is greater than the average time spend by women at the gym each week
From the summary statistics in the attached file below:
The p-value = 0.3253
Level of significance = 5% = 0.05
Therefore; it is obvious that the p-value is greater than the level of significance i.e (0.3253 > 0.05)
Hence; there is no enough evidence to reject the null hypothesis
CONCLUSION: We conclude that the mean number of minutes exercised per week is larger for men than women at the this gym.
