A(t)=A0*(1/2)^(t/30)
where t=elapsed years
A0=initial mass at t=0.
Answer:
Option c.
No damping
Step-by-step explanation:
We can easily solve this question by using a graphing calculator or any plotting tool.
The function is
f(x) = (√11)*cos(3.7x)
Which can be seen in the picture below
We can notice that f(x) is a cosine with maximum amplitude of (√11). Neither this factor nor the multiplication of x by 3.7 serve as a damping factor since they are constants.
f(x) does not present any dampening
First let’s find the equation:
a = (42-21)/(26-13)
a= 21/13
y-y1 = a(x-x1)
y-21=(21/13)(x-13)
y-21=(21/13)x - 21
y=(21/13)x-21+21
y=(21/13)x
Now we will find the other point:
X = 2 >> y =(21/13)*2 = 3.23 (not)
X = 3 >> y =(21/13)*3 = 4.84 (not)
X = 4 >> y =(21/13)*4 = 6.46 (not)
X = 5 >> y =(21/13)*5 = 8.07 (yes) find the answer
Answer:
The population of the town is 0.983 times the population of the town in the previous year.
B is correct.
Step-by-step explanation:
We are given a function which represent population of a town after t years.
It is an exponential function. Exponential function wither decease or increase it depends on factor.
b is factor which decides factor of exponential function decrease or increase.
- If b >1 then function increase
- If 0<b<1 then function decrease.
If we see our problem
Here, b=0.983<1
Function would be decrease by factor of 0.983
Thus, The population of the town is 0.983 times the population of the town in the previous year.
Step One
Find the fraction left.
Starting amount = 7/8 pound
Used amount = 1/7 of a pound.
The common denominator of these two fractions is 8 * 7 = 56
Amount left = amount started with - amount used
Amount left = 7/8 - 1/7
Amount left =
Amount left =
Amount left = 41 / 56 pounds
Step Two
Convert the Answer to ounces.
Ounces = (41/56) * 16
Ounces = 11.71 ounces almost 11 3/4