The area of a rectangle is A=LW, the area of a square is A=S^2.
W=S-2 and L=2S-3
And we are told that the areas of each figure are the same.
S^2=LW, using L and W found above we have:
S^2=(2S-3)(S-2) perform indicated multiplication on right side
S^2=2S^2-4S-3S+6 combine like terms on right side
S^2=2S^2-7S+6 subtract S^2 from both sides
S^2-7S+6=0 factor:
S^2-S-6S+6=0
S(S-1)-6(S-1)=0
(S-6)(S-1)=0, since W=S-2, and W>0, S>2 so:
S=6 is the only valid value for S. Now we can find the dimensions of the rectangle...
W=S-2 and L=2S-3 given that S=6 in
W=4 in and L=9 in
So the width of the rectangle is 4 inches and the length of the rectangle is 9 inches.
V= wlh so the answer is 56.25 or 56 1/4
Answer:
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Step-by-step explanation:
Answer:
2 x y^2 (x y - 1) (x y - 3)
Step-by-step explanation:
2x^3y^4-8x^2y^3+6xy^2
each term contains 2xy^2 so factor that out
2xy^2(x^2y^2 -4xy+3)
then lets factor the inside
what terms multiply together to give us +3 and add to -4
-3* -1 = 3 -3+-1 =-4
2 x y^2 (x y - 1) (x y - 3)
Answer:
vertical line
Step-by-step explanation:
