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2 years ago

Using the grid box, draw a net for a rectangular prism with a length of 8 units, width of 2 units and height of 3 units

Mathematics

1 answer:

prohojiy [21]2 years ago

8 0

Answer: The answer is in the attached figure.

Step-by-step explanation: We are given to draw a net for a rectangular prism of length 8 units, width 2 units and height 3 units.

What is a rectangular prism? It is a a solid three-dimensional object consisting of six faces, where each of the face is a rectangle. The same cross-section along a length of a rectangular prism makes it a prism. We also call it as a cuboid.

As given in the question, a rectangular prism ABCDEFGH is drawn in the attached figure, where length is 8 units, width is 2 units and height is 3 units.

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if a taxi charges $3.50 for the first on-fifth of a mile, then $0.55 cents for each additional one-fifth mile, how far can one t

34kurt

Let's forget for the tie being the cost ($3.5)of the 1st fifth of a mile:

Taxi charge excluding $3.5, is $13.95 - $3.5 = $10.45.

If each of the 5th (1/5) of a mile costs $0.55, then with $10.45 we can drive:
10.45/0.55 = 19 fifth of a mile. Add to that the 1st fifth = 20 fifth of a mile
20 fifth = 20 x 1/5 = 4 miles (answer)

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2 years ago

What is the degree of the polynomials below <br> 2x^7+4-3x^3+5x^8-4x

Nikolay [14]

The Answer should be 8

7 0

1 year ago

Rockwell hardness of pins of a certain type is known to have a mean value of 50 and a standard deviation of 1.2.a. If the distri

zalisa [80]

Answer:

$P(\= X \ge 51 ) =0.0062$

$P(\= X \ge 51 ) = 0$

Step-by-step explanation:

From the question we are told that

The mean value is $\mu = 50$

The standard deviation is $\sigma = 1.2$

Considering question a

The sample size is n = 9

Generally the standard error of the mean is mathematically represented as

$\sigma_x = \frac{\sigma }{\sqrt{n} }$

=> $\sigma_x = \frac{ 1.2 }{\sqrt{9} }$

=> $\sigma_x = 0.4$

Generally the probability that the sample mean hardness for a random sample of 9 pins is at least 51 is mathematically represented as

$P(\= X \ge 51 ) = P( \frac{\= X - \mu }{\sigma_{x}} \ge \frac{51 - 50 }{0.4 } )$

$\frac{\= X -\mu}{\sigma } = Z (The \ standardized \ value\ of \ \= X )$

$P(\= X \ge 51 ) = P( Z \ge 2.5 )$

=> $P(\= X \ge 51 ) =1- P( Z < 2.5 )$

From the z table the area under the normal curve to the left corresponding to 2.5 is

$P( Z < 2.5 ) = 0.99379$

=> $P(\= X \ge 51 ) =1-0.99379$

=> $P(\= X \ge 51 ) =0.0062$

Considering question b

The sample size is n = 40

Generally the standard error of the mean is mathematically represented as

$\sigma_x = \frac{\sigma }{\sqrt{n} }$

=> $\sigma_x = \frac{ 1.2 }{\sqrt{40} }$

=> $\sigma_x = 0.1897$

Generally the (approximate) probability that the sample mean hardness for a random sample of 40 pins is at least 51 is mathematically represented as

$P(\= X \ge 51 ) = P( \frac{\= X - \mu }{\sigma_x} \ge \frac{51 - 50 }{0.1897 } )$

=> $P(\= X \ge 51 ) = P(Z \ge 5.2715 )$

=> $P(\= X \ge 51 ) = 1- P(Z < 5.2715 )$

From the z table the area under the normal curve to the left corresponding to 5.2715 and

=> $P(Z < 5.2715 ) = 1$

$P(\= X \ge 51 ) = 1- 1$

=> $P(\= X \ge 51 ) = 0$

5 0

2 years ago

The quadrilateral ABCD has an area of 58 in2 and diagonal AC = 14.5 in. Find the length of diagonal BD if AC ⊥ BD.

diamong [38]

So the quadrilateral is a rhombus. RSM Is hard and etc...
Anyways if the area = $58^{2}$ and we know that one diagonal is 14.5 inches and we know that the area of a rhombus is
$\frac{D^{1} * D^{2}}{2} =$
then we can do inverse operation and do
$\frac{54}{14.5} = 4$
4 * 2 because of the inverse operation has to be done to get the right answer and then you get the length of diagonal 2 is 8 in

4 0

2 years ago

Mai traveled 15 meters in 6 seconds and Priya travels 22 meters in 10 seconds. Who was moving faster?

bonufazy [111]

Answer:

Mai because he traveled 2.5 meters in one second i believe.

Step-by-step explanation:

divide meters by seconds to see how fast each go by second.

6 0

2 years ago