3.2s:8c
4.8s:12c
Therefore, you would need 4.8g of sugar to make 12 cakes. This was solved by using ratios.
Answer:
0.0668 = 6.68% probability that the worker earns more than $8.00
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
The average hourly wage of workers at a fast food restaurant is $7.25/hr with a standard deviation of $0.50.
This means that
If a worker at this fast food restaurant is selected at random, what is the probability that the worker earns more than $8.00?
This is 1 subtracted by the pvalue of Z when X = 8. So
has a pvalue of 0.9332
1 - 0.9332 = 0.0668
0.0668 = 6.68% probability that the worker earns more than $8.00
(a+3)(a-2)
Multiply the two brackets together
a^2-2a+3a+3*-2
a^2+a-6
Answer is a^2+a-6
Answer:
5v24
Step-by-step explanation:
(v22)(5v2) = 5v(2+22) = 5v24
Answer:
Answer is c
Step-by-step explanation:
In hypothesis testing whether to accept or reject null hypothesis, normally we find one method as using confidence interval. If the test statistic lies within confidence interval, we accept otherwise we reject.
For arriving confidence intervals we add and subtract margin of error from the mean we use in null hypothesis.
Margin of error = std error * critical value of test (Z or t etc)
For the same std deviation, std error = std dev/sq rt of sample size
Thus std error is inversely proportional to the square root of sample size.
If n becomes larger, std error becomes smaller and vice versa.
So margin of error increases for smaller sample size.
Since we have to select confidence level from a small sample, we have to select one which has the greatest margin of error=18
Hence answer is
c) 71%(+/-18%)