Equation of line joining the origin and centroid of a triangle having vertices (1,
1 answer:
Step-by-step explanation:
the formulae for finding centroid is (x1+x2+x3/3 , y1+y2+y3/3)
so the coordinates of centroid is (1+3+5/3 , -2+5-6/3)
(3,-1) and other point is the origin (0,0)
we know ,the equation is
x-x1/x1-x2= y-y1/y1-y2
x-3/3-0= y-(-1)/-1-0
x-3/3=y+1/-1
-x+3=3y+3
or -x+3y=0
or x-3y=0(multiplying -1 in both sides)
so the eq is x-3y=0 ans
thank u
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