Factor completely 121x^2 - 16.
1 answer:
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So hmm check the picture below
the radius "r" is half the diameter, meaning, the diameter is 2r long
now, if the height "h" is twice "d" or 2d, then that means h = 2(2r)
thus![\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}\qquad \begin{cases} h=height\\ r=radius\\ ------\\ h=2(2r) \end{cases}\implies V=\cfrac{\pi r^2[2(2r)]}{3} \\\\\\ V=\cfrac{4\pi r^3}{3}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bvolume%20of%20a%20cone%7D%5C%5C%5C%5C%0AV%3D%5Ccfrac%7B%5Cpi%20r%5E2%20h%7D%7B3%7D%5Cqquad%20%0A%5Cbegin%7Bcases%7D%0Ah%3Dheight%5C%5C%0Ar%3Dradius%5C%5C%0A------%5C%5C%0Ah%3D2%282r%29%0A%5Cend%7Bcases%7D%5Cimplies%20V%3D%5Ccfrac%7B%5Cpi%20r%5E2%5B2%282r%29%5D%7D%7B3%7D%0A%5C%5C%5C%5C%5C%5C%0AV%3D%5Ccfrac%7B4%5Cpi%20r%5E3%7D%7B3%7D)
the radius "r" is half the diameter, meaning, the diameter is 2r long
now, if the height "h" is twice "d" or 2d, then that means h = 2(2r)
thus
Answer:
f(x) = 3 cos2(x) − 6 sin(x), 0 ≤ x ≤ 2π
We plot the function using a graphing calculator (See attached image below)
a) 1. Find the interval on which f is increasing.
f(x) increases for
x ∈ [π/2 , 7π/6] ∪ [3π/2, 11π/6]
2. Find the interval on which f is decreasing
f(x) decreases for
x ∈ [0 , π/2) ∪ (7π/6, 3π/2) ∪ (11π/6, 2π]
(b) Find the local minimum and maximum values of f
Local minimum. f = -9
Local maximum. f = 4.5
(c) 1. Find the inflection points
Please see second image attached
Points,
(x,y) = (2.50673, -2.66882)
(x,y) = (4.14456, 3.79382)
(x,y) = (5.28022, 3.79382)
2. Find the interval on which f is concave up.
x ∈ [0 , 2.50673] ∪ [4.14456, 5.28022]
3. Find the interval on which f is concave down.
x ∈ (2.50673, 4.14456) ∪ (5.28022, 2π]
