Recall the secant-tangent theorem, and you have
EA^2 = EC*CD
12^2 = 8*(x+10)
and now ED = EC+CD = 8+x+10
I suspect a typo somewhere in the murk above
1cm is worth 100km on the map that is you have 5cm they are equal 500km
A relation is (also) a function if every input x is mapped to a unique output y.
In terms of graphical representation, this implies that a graph represents a function if there doesn't exist a vertical line that intersects the graph more than once. So:
- The first graph is exactly a vertical line, so it's not a function.
- The second graph represents the function y=x, so it's a function: you can see that every possible vertical line crosses the graph only once.
- The third graph is not a function, because you can draw vertical lines that cross the graph twice.
- Similarly, in the fourth graph you can draw vertical lines that cross the graph twice
- The fifth graph is a function, because every vertical line crosses the graph once
- The last graph is a function, although discontinuous, for the same reason.
Let's simplify step-by-step.
8
x
3
−
x
−
(
10
x
−
5
x
2
−
3
x
3
)
Distribute the Negative Sign:
=
8
x
3
−
x
+
−
1
(
10
x
−
5
x
2
−
3
x
3
)
=
8
x
3
+
−
x
+
−
1
(
10
x
)
+
−
1
(
−
5
x
2
)
+
−
1
(
−
3
x
3
)
=
8
x
3
+
−
x
+
−
10
x
+
5
x
2
+
3
x
3
Combine Like Terms:
=
8
x
3
+
−
x
+
−
10
x
+
5
x
2
+
3
x
3
=
(
8
x
3
+
3
x
3
)
+
(
5
x
2
)
+
(
−
x
+
−
10
x
)
=
11
x
3
+
5
x
2
+
−
11
x
Answer:
=
11
x
3
+
5
x
2
−
11
x
Brainliest Please:)
