All categories

2 years ago

A spring has a spring constant of 20N/m. What force does the spring exert on you if the spring is compressed - 0.25 m ?

Physics

1 answer:

Triss [41]2 years ago

8 0

Answer:

Explanation:

Data obtained from the question include:

K (spring constant) = 20N/m

e (extension/compression) = 0.25 m

F (force) =?

Using the formula F = Ke, the force can be obtained as follow:

F = Ke

F = 20 x 0.25

F = 5N

You might be interested in

Physics help please..............

adoni [48]

Answer:

3.68 m/s

Explanation:

Full answer in the attached picture

7 0

2 years ago

What is the energy equivalent of an object with a mass of 2.5 kg?

Bad White [126]

This is the answer on Edgenuity 2.25*10^17

8 0

2 years ago

Read 2 more answers

In the box provided explain why living organisms contain more hydrogen atoms than any other atoms

leva [86]

Answer:it is due to present of water amount in our body. Our body consists 70%of water and 1/3of oxygen and 2/3 of hydrogen.

Explanation: human body consist of 1/3 of oxygen and 2/3 of hydrogen because oxygen contain 16 times more mass than hydrogen atom, hydrogen has only 1 proton so its atomic no. is 1 whereas oxygen has 8 proton and 8 neutrons so its atomic no.is 8 and mass is 16 so overall it takes 16 hydrogen atoms to equal to the mass of 1 oxygen atom.

6 0

2 years ago

In a double-slit experiment, light from two monochromatic light sources passes through the same double slit. The light from the

GaryK [48]

We will determine the wavelength through the relationship given by the distance between slits, this relationship is given under the function

$y = \frac{m\lambda}{d}$

Here,

m = Number of order bright fringe

$\lambda$ = Wavelength

d = Distance between slits

Both distance are the same, then

$y_1 = y_2$

$\frac{m_1\lambda_1 r}{d} = \frac{m_2\lambda_2 r}{d}$

$\frac{m_1\lambda_1}{m_2\lambda_2} =1$

Rearranging to find the second wavelength

$m_1 \lambda_1 = m_2 \lambda _2$

$\lambda_2 = \frac{m_1\lambda_1}{m_2}$

$\lambda_2 = \frac{7(629)}{8}$

$\lambda_2 = 550.3nm$

Therefore the wavelength of the light coming from the second monochromatic light source is 550.3nm

7 0

2 years ago

An proton-antiproton pair is produced by a 2.20 × 10 3 MeV photon. What is the kinetic energy of the antiproton if the kinetic e

timama [110]

Answer:

K = 80.75 MeV

Explanation:

To calculate the kinetic energy of the antiproton we need to use conservation of energy:

$E_{ph} = E_{p} + E_{ap} = E_{0p} + K_{p} + E_{0ap} + K_{ap} = m_{0p}c^{2} + K_{p} + m_{0ap}c^{2} + K_{ap}$

<em>where $E_{ph}$ : is the photon energy, $E_{0p} and E_{0ap}$ : are the rest energies of the proton and the antiproton, respectively, equals to m₀c², $K_{p} and K_{ap}$ : are the kinetic energies of the proton and the antiproton, respectively, c: speed of light, and m₀: rest mass.</em>

Therefore the kinetic energy of the antiproton is:

$K_{ap} = E_{ph} - m_{0p}c^{2} - K_{p} - m_{0ap}c^{2}$

<u>The proton mass is equal to the antiproton mass, so</u>:

$K_{ap} = E_{ph} - 2m_{0p}c^{2} - K_{p}$

$K_{ap} = 2.20 \cdot 10^{3}MeV - 2(1.67 \cdot 10^{-27}kg)(3\cdot 10^{8} \frac {m}{s})^{2} - 242.85MeV$

$K_{ap} = 2.20 \cdot 10^{3}MeV - 2(1.67 \cdot 10^{-27}kg)(3\cdot 10^{8} \frac {m}{s})^{2}(\frac{1eV}{1.602 \cdot 10^{-19}J})(\frac{1 MeV}{10^{6}eV}) - 242.85MeV$

$K_{ap} = 80.75 MeV$

Hence, the kinetic energy of the antiproton is 80.75 MeV.

I hope it helps you!

3 0

2 years ago