The steps below describe the construction of a line AG that is parallel to segment PQ and passes through a point A outside of PQ
:
Step
Step 2
PBD
Step 3
Which statement describes the next step?
The width of the compass is adjusted to DE, and an arc is drawn from Point E.
The width of the compass is adjusted to DE, and an arc is drawn from Point A
The width of the compass is adjusted to DE, and an arc is drawn from Point F
The width of the compass is adjusted to DE, and an arc is drawn from Point D.
Step
Step 2
PBD
Step 3
Which statement describes the next step?
The width of the compass is adjusted to DE, and an arc is drawn from Point E.
The width of the compass is adjusted to DE, and an arc is drawn from Point A
The width of the compass is adjusted to DE, and an arc is drawn from Point F
The width of the compass is adjusted to DE, and an arc is drawn from Point D.
2 answers:
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The question is incomplete, here is the complete question:
The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.
When will there be less than 1 g remaining?
<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.
<u>Step-by-step explanation:</u>
All radioactive decay processes follow first order reaction.
To calculate the rate constant by given half life of the reaction, we use the equation:
where,
= half life period of the reaction = 46 days
k = rate constant = ?
Putting values in above equation, we get:
The formula used to calculate the time period for a first order reaction follows:
where,
k = rate constant =
t = time period = ? days
a = initial concentration of the reactant = 12.6 g
a - x = concentration of reactant left after time 't' = 1 g
Putting values in above equation, we get:
Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.
First, simplify
Second, multiply both sides by 36. / Your problem should look like:
Third, multiply both sides by -1. / Your problem should look like:
Fourth, switch your sides. / Your problem should look like:
Answer: C) 21