Answer:
6r2+3r-3=0
two solutions are possible
r= -1
r=1/2
r = - 1 or r = 1/2
Step-by-step explanation:
From the quadratic equation;
+ 6r - 3r - 3 = 0
( + 6r) - (3r + 3) = 0
6r(r + 1) - 3 (r + 1) = 0
⇒ (r + 1) or (6r - 3) = 0
r + 1 = 0 or 6r - 3 = 0
r = - 1 or 6r = 3
Thus, the solutions to the equation are; r = - 1 or r = 1/2 since erx is never 0.
dy=9-y
dx=x
0.705303
divide 3724 by 5280
i think we have to find the answer for terms of a
p=a+4b+2c
ISOLATE A
p-4b-2c=a
answer: