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2 years ago

6

A square has an area of 90 square inches. The formula for the area A of a square with side length L is A = L^2. Find the length

of one side of the square.

1 answer:

Dovator [93]2 years ago

6 0

Answer:

Step-by-step explanation:

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2 1/5-2/3=3 1/3 <br><br> What’s the answer

Artyom0805 [142]

Answer:

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Step-by-step explanation:

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2 years ago

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The letters r and Θ represent polar coordinates. perform the following.

nexus9112 [7]

Answer:

$\boxed{(x - \frac{1 }{ 2})^{2} + y^{2} = \frac{21 }{ 4}}\\$

Step-by-step explanation:

$r = \frac{5}{r - cos\theta}\\r^{2} - rcos\theta = 5\\\\$

$\text{Use the relationships}\\r^{2} = x^{2} + y^{2}; cos\theta = \frac{ x}{r }\\$

$\begin{array}{ll}x^{2} + y^{2} - r(\frac{x }{r }) = 5 & \text{Made the substitutions } \\x^{2} + y^{2} - x = 5 & \text{Simplified } \\x^{2} -x + y^{2} = 5 & \text{Rearranged } \\x^{2} -x + \frac{1 }{ 4} + y^{2}= 5 + \frac{1 }{ 4} & \text{Completed the square } \\(x - \frac{1 }{ 2})^{2} + y^{2}= \frac{21 }{ 4} & \text{Wrote as sum of squares} \\\end{array}\\\\$

$\text{This is the equation of a circle with centre at (0.5, 0 ) and radius equal to}\\\frac{\sqrt{21} }{ 2} \approx 2.291\\$

$\boxed{(x - \frac{1 }{ 2})^{2} + y^{2}= \frac{21 }{ 4}}\\$

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2 years ago

Which expression is equivalent to logc^x^2-1/5x?

Natasha_Volkova [10]

logc(x^2-1) - (logc^5+logc^x) is the right answer.

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3 years ago

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