Answer:
The proportion of students whose height are lower than Darnell's height is 71.57%
Step-by-step explanation:
The complete question is:
A set of middle school student heights are normally distributed with a mean of 150 centimeters and a standard deviation of 20 centimeters. Darnel is a middle school student with a height of 161.4cm.
What proportion of proportion of students height are lower than Darnell's height.
Answer:
We first calculate the z-score corresponding to Darnell's height using:
We substitute x=161.4 , , and to get:
From the normal distribution table, we read 0.5 under 7.
The corresponding area is 0.7157
Therefore the proportion of students whose height are lower than Darnell's height is 71.57%
Answer:
20%
Step-by-step explanation:
Use the percent change formula: difference = % * original cost
12 - 10 = 2
The difference is 2 and the original cost is 10. Now, we have the equation
2 = % * 10. We don’t know the percentage right? So now we have to find the percentage. To do this, you will have to do 2 divided by 10, which is 0.20. Lastly, we have to turn 0.20 into a percentage by multiplying it by 100, leaving you with 20%. So therefore, 20% is the percent increase. Hope this helps!
Addition is the correct answer.
x^2 is the part where you get the second degree term. If you add x^2+x^2 you get 2x^2. If you subtract x^2-x^2 you get 0. If you multiply x^2*x^2 you get x^4, which is a fourth degree term
Answer: 11 1/9
Step-by-step explanation:
Answer:
It will be $85, 34÷ 4
will give you 8.5 then you multiply it by 10,× 10=85