The area of the triangle PQR is 17.6 square units.
Explanation:
Given that the sides of the triangle are PQ = 12 and PR = 3 and 
We need to determine the area of the triangle PQR
<u>Area of the triangle:</u>
The area of the triangle can be determined using the formula,
Substituting the values, we get,
Simplifying, we have,
Multiplying the terms, we have,
Dividing, we get,
Rounding off to the nearest tenth, we have,
Thus, the area of the triangle PQR is 17.6 square units.
<u>Answer:
</u>
f(x) = 3(x+2)(x-2)
<u>Step-by-step explanation:
</u>
We are given the following the quadratic function and we are to rewrite it in intercept or factored form:
We can factorize the given function so taking the common factors out of it to get:
The term 
is in the form 
so it can further be factorized to give:
Therefore, the factored form of the given quadratic function is f(x) = 3(x+2)(x-2).
Answer:
It cost $42 to rent a chain saw for 12 hours.
Step-by-step explanation:
Plug in 12 for h.
c = 3(12) + 6
c = 36 + 6
c = 42
m GH = 57''
________
tan 39° = opposite / adjacent
tan 39° = m GH / m HJ
tan 39° * m HJ = m GH
m HJ = m GH / tan 39°
m HJ ≈ 57'' / 0.810
m HJ ≈ 70.4'' <——<span>— measure of the segment HJ</span>
________
sin 39° = opposite / hypotenuse
sin 39° = m GH / m GJ
sin 39° * m GJ = m GH
m GJ = m GH / sin 39°
m GJ = 57'' / 0.629
m GJ ≈ 90.6'' <——— measure of the segment GJ
________
So the perimeter is
p = m GH + m HJ + m GJ
p = 57'' + 70.4'' + 90.6''
p = 218'' <——<span>— this is the answer.</span>
I hope this helps. =)
Tags: <em>perimeter right triangle sine cosine tangent sin cos tan trig trigonometry geometry</em>
