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2 years ago

The graphs below have the same shape. What is the equation of the red graph?

Mathematics

1 answer:

user100 [1]2 years ago

6 0

Step-by-step explanation:

If they have the same shape, the red graph is a translation of the blue, which is given to be y=x^2.

Since the red graph stays on the y axis at two units above the blue (y=x^2) curve, therefore the red curve is given by y=x^2+2.

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the width of a piece of rectangular land is 5m shorter rhan 1/3 of its length .find the width of the land if the length is 60m,1

aniked [119]

Answer:

If width = 60 m, length = 195 m.

If width = 150 m, length = 465 m.

Step-by-step explanation:

The area of a rectangle is l * w or length times width.

So we can set an equation (letting w = width and x = length)

w = $1/3x - 5$

Part 1: width = 60m:

60 = $1/3x - 5$

65 = $1/3x$

x = 195 m

Part 2: width = 150 m:

150 = $1/3x - 5$

155 = $1/3x$

x = 465 m

6 0

2 years ago

Use the number 913,256. Write the digit in the ten thousands place.

sergejj [24]

The 1 is in the ten thousands place

8 0

2 years ago

25 POINTS AVAILABLE

myrzilka [38]

Answer:

$\large\boxed{1.\ (-3, 0),\ r = 3}\\\boxed{2.\ (x+4)^2+(y-3)^2=36}\\\boxed{3.\ (x-2)^2+(y-1)^2=(\sqrt{34})^2}$

Step-by-step explanation:

The equation of a circle in standard form:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

1. We have the equation:

$(x+3)^2+y^2=9\\\\(x-(-3))^2+(y-0)^2=3^2$

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2. We have the center (-4, 3) and the radius r = 6. Substitute:

$(x-(-4))^2+(y-3)^2=6^2\\\\(x+4)^2+(y-3)^2=36$

3. We have the endpoints of the diameter: (-1, 6) and (5, -4).

Midpoint of diameter is a center of a circle.

The formula of a midpoint:

$\left(\dfrac{x_1+x_2}{2};\ \dfrac{y_1+y_2}{2}\right)$

Substitute:

$h=\dfrac{-1+5}{2}=\dfrac{4}{2}=2\\\\k=\dfrac{6+(-4)}{2}=\dfrac{2}{2}=1$

The center is in (2, 1).

The radius length is equal to the distance between the center of the circle and the endpoint of the diameter.

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the coordinates of the points (2, 1) and (5, -4):

$r=\sqrt{(5-2)^2+(-4-1)^2}=\sqrt{3^2+(-5)^2}=\sqrt{9+25}=\sqrt{34}$

Finally we have:

$(x-2)^2+(y-1)^2=(\sqrt{34})^2$

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2 years ago

Brainly.com fam help me fine the value of the x thank you so much

Thepotemich [5.8K]

First you subtract 47 from both sides (-47 from 47 and -47 from 32)
Then you get -3x = -15
Divide -3 from -3x and -3 from -15
Leaving you with X = 5

5 0

2 years ago

Plssss helpp brainliest will b givenn

omeli [17]

Answer:

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers